How many moles of O2 are required to react completely with 14.8 moles of AL? 4AL -> 2AL2O3

1 Answer
Jane
Feb 23, 2018

#11.1# moles

Explanation:

Given equation is, # 4 Al + 3O_2 = 2Al_2 O_3#

So, #3# moles of #O_2# are required for reacting with #4# moles of #Al#

So,to react with #14.8# moles of #Al# , moles of #O_2# required will be #14.8 (3/4) = 11.1# moles

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