How many moles of oxygen will be needed to completely oxidize 4 moles of #CH_4 + O_2 -> CO_2 + H_2O#?

1 Answer
Mar 20, 2016

Answer:

#4CH_4(g) + 8O_2(g) rarr 4CO_2(g) + 8H_2O(l)#

Explanation:

The equation above is stoichiometrically balanced, and represents the combustion of 4 mol methane to give 4 mol carbon dioxide and 8 mol of water. 8 mol of dioxygen gas are required for complete combustion.