How many moles of oxygen would have be consumed to produce 68.1 g of water in the reaction #C_3H_8 + 5O_2 -> 3CO_2 + 4H_2O#?

1 Answer
Jul 8, 2016

Answer:

Approx. #20*mol" dioxygen gas"#

Explanation:

#"Moles of water"# #=# #(68.1*g)/(18.01*g*mol^-1)# #=# #3.78*mol#

Given the stoichiometry, clearly there are #5/4xx3.78*mol# #"dioxygen gas"# required. What is the equivalent mass?