How many moles of potassium are there in #2.4 \times 10^21# atoms K?

1 Answer
Nov 21, 2017

0.0040 mols of potassium.


In order to do the conversion:

#2.4*10^21 "atoms of K"*("1 mol of K"/(6.022*10^23 "atoms")) = 0.0040 "mols of K"#

Since there are #6.022*10^23# atoms in 1 mol of a substance (Avogadro's number), we use that conversion factor in the dimensional analysis.