Question

How many moles of potassium chlorate must be used to produce 6 moles of oxygen gas?

Answer 1

Following the equation:
`2KClO_3 => 2KCl + 3O_2`

where, `KCl` = Potassium Chloride,
`O_2` = Oxygen Gas
`KClO_3` = Potassium Chlorate

So, 6 moles of Oxygen Gas `O_2` has been given to you.
To calculate the number of moles for potassium chlorate `KClO_3`, use the mole ratio.

Looking closely at the equation,
If 3 moles of `O_2` gives you 2 moles of `KClO_3` because `3 -: 3 xx 2`,
then 6 moles of `O_2` must give you:
`6 -: 3 xx 2` = 4 moles of `KClO_3`

To find the number of moles for another compound in the same equation:
number of moles given to you from compound 1 `-:` the front number for compound 1 `xx` the front number for another compound.

Therefore, 4 moles of potassium chlorate must be used to produce 6 moles of oxygen gas.