How many moles of silver are in a 0.648 g coin of pure silver?

Calculate the quotient $\text{mass"/"molar mass}$ for the molar quantity...
And here, we have $\frac{0.648 \cdot g}{107.9 \cdot g \cdot m o {l}^{-} 1} = 6.0 \times {10}^{-} 3 \cdot m o l$.
Given that the $\text{Avocado number} \equiv 6.022 \times {10}^{23} \cdot m o {l}^{-} 1$, can you tell me that NUMBER of silver atoms that constitute such a mass. You have all the data to do so............