# How many moles of sodium hydroxide contained in 300 mL of a .100M NaOH solution?

$\text{Number of moles of sodium hydroxide}$
$= 300 \cdot m L \times {10}^{-} 3 L \cdot m {L}^{-} 1 \times 0.100 \cdot m o l \cdot {L}^{-} 1$.
$= 300 \cdot \cancel{m L} \times {10}^{-} 3 \cancel{L} \cdot \cancel{m {L}^{-} 1} \times 0.100 \cdot m o l \cdot \cancel{{L}^{-} 1}$
$= 3.00 \times {10}^{-} 2 \cdot m o l$