# How many moles of sodium sulfate are present in .1000 g of the compound?

Approx. $7 \times {10}^{-} 4$ $\text{moles}$
$\text{Moles of sodium sulfate"="Mass"/"Molar Mass}$ $=$
$\frac{0.1000 \cdot g}{142.04 \cdot g \cdot m o {l}^{-} 1}$ $=$ ??mol.