How many moles of solid aluminum, Al(s) will react completely with 6 moles of HCI (aq)?

1 Answer
Sep 16, 2017

Answer:

Approx. #2*mol# metal, i.e. approx. #54*g#.....

Explanation:

We write the oxidation reaction......

#Al(s) rarr Al^(3+) + 3e^(-)# #E^@=1.662*V#

And we also write the reduction reaction.....

#H^(+) +e^(-) rarr 1/2H_2(g) # #E^@=0*V#

And thus......

#Al(s) +3H^+ rarrAl^(3+) + 3/2H_2(g)# #;E_"cell"^@=1.662*V#

And because #E_"cell"^@# is positive, the oxidation reaction as written is spontaneous. Given the stoichiometry if we got 6 equiv. hydrochloric acid, two equivs of aluminum should be oxidized.