# How many moles of solute particles are present in 1 mL (exact) of aqueous 0.0060 M Ba(OH)_2?

$3 \times 1 \times {10}^{-} 3 \cancel{L} \times 6.0 \times {10}^{-} 3 \cdot m o l \cdot \cancel{{L}^{-} 1}$ $=$ $18 \times {10}^{-} 6 \cdot m o l$
Barium hydroxide is an electrolyte that gives $B {a}^{2 +}$ and $2 \text{ equiv } H {O}^{-}$ ions upon dissolution.
$\text{Volume "(L)xx"concentration } \left(m o l \cdot {L}^{-} 1\right)$ $=$ $\text{moles, amount of subtance.}$