The #""^19F# is almost 100% abundant. Because in each fluorine nucleus, there are necessarily #"9 protons"#, why necessarily?, there must be 10 neutrons, neutral massive particles, in the fluorine nucleus.
Note that #""^19F# is 100% spin active #("I=1/2")#, it can be regularly used in #"NMR spectroscopy"#. Because fluorine chemistry is a trifle hazardous, this spectroscopy is not as well developed as that of #""^1H# or #""^13C#.