How many neutrons are there in #""_6^12"C"^(4-)#?

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Answer 1 · 2018-02-20T12:27:38

#6#

We know that, In a Nucleon , Topmost Number is Mass Number and The Bottom Number is Atomic Number.

And More,

Mass Number = Atomic Number + Number of Neutrons Present in That Atom.

So, Number of Neutrons = Mass Number - Atomic Number

In this case,

Mass Number = #12#

Atomic Number = #6#

So, Number of Neutrons = #12 - 6# = #6#

Hence Explained.

Answer 2 · 2018-02-20T13:13:59

#6# neutrons

If an isotope, atom, or an ion is expressed in the form of

#""_Y^ZX#

then #Y# is the proton number, #Z# is the mass number, and #X# is the element.

Here, #Z=12#, #Y=6#. #X=C^(4-)#

We know that this is carbon-12 ion, so its mass number is #12# and it has #6# protons.

The mass number is the total number of neutrons and protons added together.

So, there are #12-6=6# neutrons in this carbon-12 anion.