How many nitrogen molecules are in 2.4 moles of N_2?

Jun 14, 2016

$1.44 \cdot {10}^{24}$molecules${N}_{2}$

Explanation:

Using Avogadro's constant of 1 mole is equal to ${6.02810}^{23}$molecules, we can convert moles to molecules.

$2.4 m o l {N}_{2} \cdot \frac{{6.02810}^{23} m l c s {N}_{2}}{1 m o l {N}_{2}}$

$2.4 \cancel{m o l {N}_{2}} \cdot \frac{{6.02810}^{23} m l c s {N}_{2}}{1 \cancel{m o l {N}_{2}}}$

$1.44 \cdot {10}^{24}$molecules${N}_{2}$

This would means that there would be

$2.88 \cdot {10}^{24}$atoms${N}_{2}$

as there are two atoms of Nitrogen in each of the molecules.