Question

How many number of moles of ammonia can be formed from `"0.25 moles of N"_2` gas?

Answer 1

`"0.5 mol NH"_3`

Explanation:

Reaction equation for formation of ammonia `("NH"_3)` is

`"N"_2 + "3H"_2 -> "2NH"_3`

From above equation,
`1` mole of `"N"_2` reacts to give `2` moles of `"NH"_3`

So, `0.25` mol of `"N"_2` will give

`0.25 cancel("mol N"_2) × ("2 mol NH"_3)/(1 cancel("mol N"_2)) = "0.5 mol NH"_3`

Answer 2

`0.50 "mol NH"_3`

Explanation:

1. Let us write the stoichiometric equation for synthesis of Ammonia:
   `N_2(g)+ 3H_2(g)-> 2NH_3(g)`

2. Use molar ratios
   `0.25 cancel("mol N"_2) * (2 "mol NH"_3)/ (1cancel("mol N"_2))=`

`0.50 "mol NH"_3`