Question

How many ounces of pure water would have to be added to 30 ounces of 30% solution of alcohol to reduce the original solution to 25%?

Answer 1

`6` ounces of pure water added to `30` ounces `30%` alcohol solution to get `36` ounces of `25%`solution.

Explanation:

Let `x` ounces of pure water is added to `30` ounces `30%`

alcohol solution to reduce it to `25%` solution. Balancing alcohol

content ,we get `x*0+ 30* 30/cancel100= (x+30)*25/cancel100`

or `900 = 25 x +750 or 25 x = 900-750 or 25 x =150`

`:. x=150/25=6` ounce. Hence `6` ounces of pure water added

to `30` ounces `30%` alcohol solution to get `36` ounces of

`25%` solution. [Ans]