Question

How many oxygen molecules will be produced from the decomposition of 18.4g of water?

Answer 1

Approx...`3.0xx10^23` `"dioxygen molecules"`

Explanation:

We (i) write the stoichiometric equation....

`H_2O(l) rarrH_2(g) + 1/2O_2(g)`

And (ii) we determine the equivalent quantity of water...

`n_"water"=(18.4*g)/(18.01*g*mol^-1)=1.02*mol`

And so (iii) we get half an equiv of dioxygen molecules, i.e. `0,51*mol`...a number of `1/2*molxx6.022xx10^23*mol^-1=`
`3.07xx10^23` `"dioxygen molecules"`...