How many particles are in 6.84 grams of #Li_2Co_3#?

It is 73.890 g/mol.

1 Answer
anor277
Nov 29, 2016

#6.84*g# represents #9.26xx10^-2*mol# of #"lithium carbonate"#.

Explanation:

And thus this molar quantity represents #2xx9.26xx10^-2*mol# of #"lithium atoms"#, #9.26xx10^-2*mol# of #"carbon atoms"#, and #3xx9.26xx10^-2*mol# of #"oxygen atoms"#.

To get the molar quantity of #"lithium carbonate"# I simply took the quotient, #"mass"/"molar mass"#, i.e. #(6.84*g)/(73.89*g*mol^-1)=??*mol#.

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