How many particles of NaCl are needed to make a solution of 483 mL with a molarity of .25?

1 Answer
Junaid Mirza
Apr 20, 2018

#7.27 × 10^22\ "particles"#

Explanation:

#"Molarity" = "Moles of solute"/"Volume of solution (in litres)"#

#"0.25 M" = "n"/"0.483 mL"#

#"n = 0.12075 mol"#

Number of particles#= 0.12075 cancel"mol" × (6.022 × 10^23\ "particles")/(1 cancel"mol") = 7.27 × 10^22\ "particles"#

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