How many real number solutions are there to the equation 0=-3x^2+x-40=−3x2+x−4?
2 Answers
No real solutions it has.
Explanation:
Doing the first step of quadratic formula, i.e. finding the discriminant gives us the answer:
if d < 0, no real solution,
if d = 0, one solution
and if d > 0, the quadratic equation has two solutions.
In this case,
It has no real roots.
Please see below.
Explanation:
Here,
Comparing with
Hence , the equation has no real root , but two complex roots.
i.e. two solutions in