How many real roots does (x^2 +1)^2 - x^2 = 0 has?

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Answer 1 · 2018-02-07T20:31:22

See explanation.

#(x^2+1)^2-x^2=0#

#(x^2+1-x)(x^2+1+x)=0#

#x^2-x+1=0 vv x^2+x+1=0#

#x^2-x+1=0#

#Delta=(-1)^2-4*1*1=1-4=-3#

This equation has NO real roots.

#x^2+x+1=0#

#Delta=1^2-4*1*1=1-4=-3#

This equation has NO real roots.

Answer:

The original equation has NO real roots.