# How many significant figures are there in the result of the following calculation? (4.321/28) x (6.9234 x 10)

##### 1 Answer

One significant figure.

#### Explanation:

You're dealing with multiplication and division, so you know that the answer must have as many significant figures as the measurement with the **least number of sig figs**.

In your case, you have

#color(white)(1)4.321 " "->" "# four sig figs#color(white)(12.1)28 " "->" "# two sig figs#6.9234 " "->" "# five sig figs#color(white)(12.1)10 " "->" "# one sig fig

So, you know that the answer must be rounded to **one significant figure** because that is how many sig figs you have for your least precise measurement.

Since your expression contains a couple of parentheses, focus on solving these first. Keep in mind that you don't really need parentheses for same-level operations, you can solve these left-to-right.

#(4.321/28) xx (6.9234 xx 10)#

You're going to be doing a multi-step calculation, so make sure that you keep *enough sig figs* for each step to avoid the loss of significance.

As a general rule, it's better to have too many sig figs for each step than too few, so I'll go with

#4.321/28 = 0.15432#

#6.9234 xx 10 = 69.234#

Put this together to get

#0.15432 xx 69.234 = 10.684#

Finally, round the answer to **one significant figure** to get

#(4.321/28) xx (6.9234 xx 10) = 10#