# How many silver atoms are there in 2.00 moles of silver?

$1 \cdot m o l$ simply specifies a number, i.e. ${N}_{A} = 6.0222 \times {10}^{23} \cdot m o {l}^{-} 1$.
And, thus in $2.00 \cdot m o l$ of silver, there are $2 \cdot m o l \times {N}_{A}$ $=$ $6.022 \times {10}^{23} \cdot \cancel{m o {l}^{-} 1} \times 2 \cdot \cancel{m o l} = 1.20 \times {10}^{24}$ $\text{individual silver atoms.}$