How many solutions would #0=y^2+10y+25# have? On a graph

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Answer 1 · 2018-05-04T09:56:57

1 solution.

It would have 1 solution.

#y^2+10y+25=0#

Factor,

#(y+5)^2=0#

Solve,

#y=-5#

Hence, there is 1 solution.

Graph: graph{x^2+10x+25 [-10, 10, -5, 5]}