# How many Sulfur atoms are in 0.42 mol S?

If I have half a dozen sulfur atoms; clearly I have 6 sulfur atoms. If I have 0.42 mol of sulfur there are $0.42 \times {N}_{A}$ sulfur atoms, where ${N}_{A} =$ Avogadro's number.
The mole is simply a number, admittedly a very large number: ${N}_{A} = 6.022 \times {10}^{23}$. So, in fact I have $0.42 \times {N}_{A}$ sulfur atoms.
To expand, Avogadro's number, ${N}_{A}$, is simply the link between the micro world of atoms and molecules, with the macro world of grams and kilograms. If I have a mass of $32.06$ $g$ of sulfur, which I can easily weigh out on a bench, I know, to a very good approximation, that I have $6.022 \times {10}^{23}$ sulfur atoms (these may be individual atoms or they may be part of ${S}_{8}$ rings - the number of sulfur atoms is determined directly!)