How many three letter arrangements of the word ALGORA are there?

1 Answer

72 arrangements

Explanation:

This is a permutation question in that we care about the order of the letters. The general formula is:

#P_(n,k)=(n!)/((n-k)!); n="population", k="picks"#

If all the letters were different, we'd have:

#P_(6,3)=(6!)/(3!)=720/6=120#

However, we have to deal with the repeated A.

Unfortunately, we can't simply divide by #2!# to get rid of the double A because not all our permutations are going to have it. And so we have to deal with the cases separately - one where at most one A is selected, and the other with both As.

At most one A

That's 5 distinct letters and we're selecting 3 of them:

#P_(5,3)=(5!)/(2!)=120/2=60#

Both As

There are 4 letters that are not A and it can be placed in any one of 3 places (first letter, second, or third). That gives:

#4xx3=12#

We now add these results:

#60+12=72#