How many total atoms are in 0.810 g of #P_2O_5#?

1 Answer
Aug 3, 2017

Answer:

Approx. #2.4xx10^22# #"individual atoms......"#

Explanation:

We work out the molar quantity of #P_4O_10#, which has a molecular mass of #283.89*g*mol^-1#.

And to get the molar quantity we take the quotient......

#(0.810*g)/(283.89*g*mol^-1)=2.86xx10^-3*mol#.

Now it is a fact that #"1 mole"# of stuff contains #6.022xx10^23# individual items of stuff. Since the stuff in this case is the #P_4O_10#, there are #14xx6.022xx10^23# individual atoms in one mole of stuff.

And we take the product.......

#2.86xx10^-3*molxx14xx6.022xx10^23*"atoms"*mol^-1#

#=2.41xx10^22*"individual atoms"#.........