Question

How many total atoms are in 0.810 g of `P_2O_5`?

Answer 1

Approx. `2.4xx10^22` `"individual atoms......"`

Explanation:

We work out the molar quantity of `P_4O_10`, which has a molecular mass of `283.89*g*mol^-1`.

And to get the molar quantity we take the quotient......

`(0.810*g)/(283.89*g*mol^-1)=2.86xx10^-3*mol`.

Now it is a fact that `"1 mole"` of stuff contains `6.022xx10^23` individual items of stuff. Since the stuff in this case is the `P_4O_10`, there are `14xx6.022xx10^23` individual atoms in one mole of stuff.

And we take the product.......

`2.86xx10^-3*molxx14xx6.022xx10^23*"atoms"*mol^-1`

`=2.41xx10^22*"individual atoms"`.........