How many two-digit numbers are divisible by both 2 and 3?

1 Answer
Apr 13, 2018

7575 numbers are divisible by 22 and 33.

Explanation:

The two digit numbers are 1010 to 9999. So there are 9090 two digit numbers. Half of them are even, so 4545 two digit numbers are divisible by 22.

The lowest two digit number divisible by 33 is 1212. And out of 9090 numbers, every 33 is divisible by 33. So there are 3030 two digit number divisible by 33.

So 45 + 30 = 7545+30=75.