# How much aluminum can be retrieved from 55.6 g of aluminum oxide, Al_2O_3?

Approx. $30 \cdot g$ of aluminum metal
$\text{Moles of alumina}$ $=$ $\frac{55.6 \cdot g}{101.96 \cdot g \cdot m o {l}^{-} 1} = 0.545 \cdot m o l$.
Given that each mole of alumina contains 2 moles of aluminum metal, there are 1.09*molxx26.98*g*mol^-1=??g
The production of aluminum from alumina is highly energy intensive, even given that aluminum (as $A {l}_{2} {O}_{3}$) is the third most abundant element in the Earth's crust. The aluminum-oxygen bond is very strong, and much electrical energy must be supplied for reduction.