How much Aluminum Chloride in grams is needed to completely precipitate 1.74 grams of K2SO4 (FW=174 g/mol)?
The question is unsound...
We could change it to how much
And here, we would write the stoichiometric equation...
And thus moles of potassium sulfate is equal to moles of barium nitrate.
And thus we require an equivalent quantity of barium nitrate...
Here it is: 0.89 grams
is the balanced chemical reaction.
Now you have
Therefore you need 0.0067 mole of
(MW of it is 133.5 grams). Therefore total amount needed to complete this reaction is
You need 0.89 grams of