# How much carbon can be obtained from 65.3 g of Ca(C_2H_3O_2)_2?

Jul 29, 2016

Approximately $19.8$ grams

#### Explanation:

Approximate the molar mass of the constituent elements as follows:

$C a : 40$ g/mol

$C : 12$ g/mol

$H : 1$ g/mol

$O : 16$ g/mol

Then the mass of $C a {\left({C}_{2} {H}_{3} {O}_{2}\right)}_{2}$ is:

$40 + 2 \left(\left(2 \cdot 12\right) + \left(3 \cdot 1\right) + 2 \cdot \left(16\right)\right)$

$= 40 + 2 \left(24 + 3 + 32\right)$

$= 40 + 2 \cdot 59$

$= 158$ g/mol

of which $4 \cdot 12 = 48$ g/mol is carbon.

So in $65.3 \text{g}$ of $C a {\left({C}_{2} {H}_{3} {O}_{2}\right)}_{2}$, the mass of carbon is:

$65.3 \cdot \frac{48}{158} \approx 19.8 \text{g}$