How much displacement will a coil spring with a spring constant of 120 N/m achieve if it is stretched by a 60 N force?

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Answer 1 · 2017-10-15T18:48:18

#DeltaS=0.5"m"#

Hooke's Law for stretching of a spring:

#color(blue)(F_"sp"=kDeltaS)#

where

#k# is the spring constant

#Deltas# is the displacement of the spring from equilibrium

We want to find #Deltas#, so we can isolate that variable:

#=>color(blue)(DeltaS=(F_"sp")/k)#

Given that:

#=>DeltaS=(60" N")/(120" N"//"m")#

#=>color(blue)(=0.5"m")#

#:.# The spring is stretched by half a meter, or about 50 centimeters.