How much distance does a car with an acceleration of 4.0 m/s^2 travel as it goes from 10 m/s to 30 m/s?

1 Answer
Jan 7, 2016

100 m

Explanation:

Use the third equation of motion (time independent)
v^2 - u^2 = 2ax
and the variables v, u and a
Final velocity v = 30 m s^-1
Initial velocity u = 10 m s^-1
acceleration a = 4 m s^-2

Solution:

v^2 - u^2 = 2ax
30^2 - 10^2 = 2 xx 4 xx x
900 - 100 = 8 x
800 = 8 x
or 100 meters