# How much heat is absorbed when 52.3 g H_2O(l) at 100 C and 101.3 kPa is converted to steam at 100 C? The molar heat of vaporization of water is 40.7 kJ/mol.

Jun 12, 2017

Approx. $+ 100 \cdot k J$................

#### Explanation:

We assess the energy transfer involved in the reaction......

${H}_{2} O \left(l\right) + \Delta \rightarrow {H}_{2} O \left(g\right)$

Both the water and the steam are $100$ ""^@C in temperature.

We are given that $\Delta {H}_{\text{vaporization}} = 40.7 \cdot k J \cdot m o {l}^{-} 1$.

And thus Delta=(52.3*g)/(18.01*g*mol^-1)xx40.7*kJ*mol^-1=??kJ

How would we change the answer if we were asked to assess the energy transfer when the same quantity of steam CONDENSED to give water at $100$ ""^@C?