How much heat is evolved when 907 kg of Ammonia is produced according to the following equation? (Assume that the reaction occurs at constant pressure) #N_2(g)# + #3H_2(g)# #rarr# #2NH_3(g)# ; #DeltaH# = -91.8 kJ Thank you so much! :)
1 Answer
Feb 28, 2018
Explanation:
Start by converting 907kg of
Next, divide
Finally, multiply