How much heat is required to melt 52.8 g of water?

Apr 2, 2016

${H}_{2} O \left(s\right) \rightarrow {H}_{2} O \left(l\right)$, at 0""^@ $C$.
The latent heat of fusion of water is $333.55$ $J \cdot {g}^{-} 1$. This is actually exceptionally large, and reflects the strength of hydrogen bonding as an intermolecular force.
So, the heat required to melt the given quantity of water, under the given conditions is, $333.55$ $J \cdot \cancel{{g}^{-} 1}$ $\times$ $52.8$ $\cancel{g}$ $=$ ??J