How much heat is required to melt 52.8 g of water?

1 Answer
anor277
Apr 2, 2016

We want the energy change for the transition:

H_2O(s) rarr H_2O(l)H2O(s)→H2O(l), at 0""^@0∘ CC.

Explanation:

The latent heat of fusion of water is 333.55333.55 J*g^-1J⋅g−1. This is actually exceptionally large, and reflects the strength of hydrogen bonding as an intermolecular force.

So, the heat required to melt the given quantity of water, under the given conditions is, 333.55333.55 J*cancel(g^-1) xx 52.8 cancelg = ??J

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