# How much heat is required to vaporize 80.6 g of water at 100 C? The heat of vaporization of water at 100 C is 40.7 kJ/mole.?

Jul 17, 2016

The heat being added to a substance during a phase change does not raise the Temperature, instead, it's being used to break the bonds in the solution.

#### Explanation:

So, to answer the question, you must convert grams of water to moles.

$80.6$ $g \cdot \frac{1 m o l}{18 g} = x \text{ moles}$ of ${H}_{2} O$

Now, multiply moles by the heat of vaporization, $40.7$ $k J$/$m o l$$e$ and you should get your answer.

This is the amount of heat applied to water to completely break the bonds between water molecules so it can completely vaporize.