# How much #KI# is present in .836 L of a 1.82 M solution, assuming the solvent is #H_2O#?

##### 1 Answer

Mar 11, 2016

#### Answer:

The solution contains 252 g of

#### Explanation:

**Step 1. Calculate the moles of #"KI"#.**

Your solution contains 1.82 mol of

So, in 0.836 L of solution you have

**Step 2. Convert moles of #"KI"# to grams of #"KI"#**

Hence,