Question

How much lead can be extracted from 254.3 g of lead (IV) oxide?

Answer 1

Approx. `215*g`.

Explanation:

`"Moles of plumbic oxide"` `=` `(254.3*g)/(239.3*g*mol^-1)`, which is slightly over a mole.

And thus an equivalent quantity of lead metal can be extracted,

i.e.: `(254.3*g)/(239.3*g*mol^-1)xx207.2*g*mol^-1` `=` `??g`