How much mass is in a 3.25-mole sample of NH_4OH?

Jun 20, 2018

$\text{114 g}$.

Explanation:

First, we'll need to find out the mass of $1$ mole of $N {H}_{4} O H$.
To do this, we need to add up the masses of one mole, or molar masses, of its constituent atoms:

$\text{1 mole" = N+Hxx4+O+H = "14.01 g/mol" + "1.008 g/mol" xx 4 + "16.00 g/mol" + "1.008 g/mol" = "35.05 g/mol}$

Now, to find the mass of $3.25$ moles of $N {H}_{4} O H$, we'll just need to multiply its molar mass by $3.25$:

$\text{mass" = "number of moles" xx "mass of 1 mole}$
$= \text{number of moles" xx "molar mass}$
$= \text{3.25 mol" xx "35.05 g/mol" = "114 g}$