# How much of an alloy that is 30% copper should be mixed with 600 ounces of an alloy that is 80% copper in order to get an alloy that is 40% copper?

Nov 14, 2016

The amount is $= 2400$ ounces

#### Explanation:

Let $x$ ouncs be amount of the alloy

And the total $= x + 600$ ounces

Therefore the balance with respect to copper is

$x \cdot 0.3 + 600 \cdot 0.8 = \left(x + 600\right) \cdot 0.4$

$0.3 x + 480 = 0.4 x + 240$

$0.1 x = 240$

$x = 2400$ ounces