Question

How much of an alloy that is 30% copper should be mixed with 600 ounces of an alloy that is 80% copper in order to get an alloy that is 40% copper?

Answer 1

The amount is `=2400` ounces

Explanation:

Let `x` ouncs be amount of the alloy

And the total `=x+600` ounces

Therefore the balance with respect to copper is

`x*0.3 +600*0.8=(x+600)*0.4`

`0.3x+480=0.4x+240`

`0.1x=240`

`x=2400` ounces