How much power is needed to accelerate an object with a mass of #6 kg# and a velocity of #3 m/s# at a rate of #9 m/s^2#?

1 Answer
Apr 22, 2016

#P=162W#

Explanation:

#"work is described as "W=F*Delta x#
#F:"Force"#
#Delta x="displacement of object"#
#"we can write F=m*a"#
#W=m*a* Delta x#

#Power=P=W/(Delta t)#

#P=(m*a*Delta x)/(Delta t)#

#(Delta x)/(Delta t)=v" velocity"#

#P=m*a*v#

#m=6 kg" "a=9m/s^2" "v=3 m/s#

#P=6*9*3#

#P=162W#