How much power is produced if a voltage of 15 V is applied to a circuit with a resistance of 5 Omega?

May 19, 2016

Power is $45$ $W$

Explanation:

$\text{Current in this circuit" = "voltage"/ "resistance}$
i.e. $I = \frac{V}{R}$

so $I = \frac{15}{5}$ = $3$ $A$

Power= $\text{voltage" xx "current}$ i.e. $P = V . I$ = $15 \times 3$ = $45 W$.
Or ${I}^{2} \times R$ = $3 \times 3 \times 5$ = $45$ $W$.

where $V$=voltage $I$= current $R$= Resistance .