# How much power is produced if a voltage of 2 V is applied to a circuit with a resistance of 16 Omega?

May 22, 2018

$\text{0.25 W}$

#### Explanation:

We know that

$\text{electric power}$ $= \text{voltage" xx "current}$

Given:

• $\text{resistance} = 16 \setminus \Omega$
• $\text{voltage" \ = \ "2 V}$

According to Ohm's Law,

$V = I R$

$\therefore I = \frac{V}{R}$

So

$I = \text{2 V"/(16 \ Omega) =1/8 \ "A}$

Therefore,

$P = V I$

$P = \text{2 V" * 1/8 \"A}$

$P = \frac{1}{4} \setminus \text{W" = "0.25 W}$