How much power is produced if a voltage of #7 V# is applied to a circuit with a resistance of #42 Omega#?

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Answer 1 · 2018-06-29T08:33:29

The power is #=1.17W#

The power is

#P=UI#

and Ohm's Law is

#U=RI#

#I=U/R#

Therefore,

#P=U*U/R=U^2/r#

The voltage is #U=7V#

The resistance is #R=42 Omega#

Therefore,

The power is

#P=(7^2)/42=49/42=1.17W#

Answer 2 · 2018-06-29T13:38:45

Approximately #1.17# watts.

Power in here is given by the equation:

#P=V^2/R#

where:

#P# is the power in watts

#V# is the voltage in volts

#R# is the resistance in ohms

So, we get:

#R=(7 \ "V")^2/(42 \ Omega)#

#=(49 \ "V"^2)/(42 \ Omega)#

#~~1.17 \ "W"#