# How much thermal energy is absorbed by 750 grams of water when its temperature increases from 15.4 C to 86.3°C?

Nov 28, 2016

222.27 kJ

#### Explanation:

$Q = m \cdot c \cdot \Delta T$

Where ,

Q = Thermal Energy
m = mass of the matter,
c = Specific heat
ΔT = Temperature difference [ Delta T]

So there is "-

m = 750 gm
c = 4.184 Joule
ΔT = 70.9 Degree C

$Q = 750 \cdot 4.184 \cdot 70.9 = 222248$

22248 Joules
or 222.48 kJ