Question

How should I do this question that is in the image below?33

Answer 1

see explanation.

Explanation:

`BD=x/cos30^@=(2x)/sqrt3`
`BE=(BD)/sin60=((2x)/sqrt3)/(sqrt3/2)=(4x)/3`
In `DeltaABE, y/sintheta=(BE)/sin45`,
`=> y=((4x)/3)/(1/sqrt2) * sintheta=(4sqrt2xsintheta)/3`