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How to calculate log 0.9821*10^6 ?

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anor277 Share
Jun 18, 2018

Answer:

Should you not specify the BASE of the logarithmic function...?

Explanation:

If it is #log_(10)0.9821xx10^6#...this is approx. equal to #6#...we get a more or less exact value from the calculator...#log_(10)0.9821xx10^6-=5.992#...

But if we use natural logarithms (and since the base is UNSPECIFIED I would be justified in assuming this, the most natural base) we got...

#log_(e)0.9821xx10^6-=13.797#...

As always when we write #log_a b=c#...I ask to what power I raise the base #a# to get #b#...and here #a^c=b#. By way of example....

#log_10(0.1)=log_10(10^(-1))=-1#

#log_10(100)=log_10(10^(2))=2#

#log_10(1000000)=log_10(10^(+6))=6#

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