How to calculate the force of gravitational attraction between a person (mass=75 kg) & Earth (mass 5.98x10^24 kg and mean radius 6.37x10^6m) ?

Then teach the underlying concepts
Don't copy without citing sources
preview
?

Write a one sentence answer...

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer

Describe your changes (optional) 200

10
Apr 24, 2016

$740 N$

Explanation:

The gravitational force can be calculated with the formula:

$\textcolor{b l u e}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} {F}_{g} = \frac{G M m}{R} ^ 2 \textcolor{w h i t e}{\frac{a}{a}} |}}}$

where:
${F}_{g} =$gravitational force
$G =$gravitational constant
$M =$mass of Earth
$m =$mass of object
$R =$distance from earth's centre to object's centre

Substitute your known values into the formula to determine the gravitational force. Assuming that the person is standing on the surface of the Earth, the value of $R$ would be the radius of the Earth.

${F}_{g} = \frac{G M m}{R} ^ 2$

${F}_{g} = \frac{\left(6.67 \times {10}^{-} 11 \frac{N \cdot {m}^{2}}{k {g}^{2}}\right) \left(5.98 \times {10}^{24} k g\right) \left(75 k g\right)}{6.37 \times {10}^{6} m} ^ 2$

${F}_{g} = 737.24 N$

${F}_{g} \approx \textcolor{g r e e n}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} 740 N \textcolor{w h i t e}{\frac{a}{a}} |}}}$

Just asked! See more
• 4 minutes ago
• 5 minutes ago
• 7 minutes ago
• 8 minutes ago
• 24 seconds ago
• 2 minutes ago
• 2 minutes ago
• 3 minutes ago
• 3 minutes ago
• 3 minutes ago
• 4 minutes ago
• 5 minutes ago
• 7 minutes ago
• 8 minutes ago