How to calculate the number of protons in 1.00 g of #C_60#?

1 Answer
anor277 · Truong-Son N.
Feb 17, 2018

Well, what is the molar quantity of #C_60#?

Explanation:

I make it ...#(1.00*g)/(60xx12.011*g*mol^-1)=1.39xx10^-3*mol#...

And so the number of nucular protons is given by the product...

#1.39xx10^-3*molxx6*"protons/carbon"xx60*"carbons"xx6.022xx10^23*mol^-1#

#=??*"protons"#

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