How to calculate this?#lim_(x->oo)(ln((x+2)/x)-ln((x+1)/(x-1))+1)#

Question

716 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-25T19:32:50

#1#

#lim_(x->oo)(ln((x+2)/x) - ln((x+1)/(x-1)) + 1)#

#=lim_(x->oo)(ln(1+2/x) - ln(1+2/(x-1)) + 1)#

#=ln(1+0) - ln(1+0) + 1#

#=0-0+1#

#=1#

Answer 2 · 2017-04-25T19:35:32

#1#

#ln((x+2)/x)-ln((x+1)/(x-1))+1 = ln((e (x + 2) (x - 1))/(x(x+1)))#

and

#lim_(x->oo)(ln((x+2)/x)-ln((x+1)/(x-1))+1) = lim_(x->oo)ln((e (x + 2) (x - 1))/(x(x+1)))=#
#= ln(lim_(x->oo)(e (x + 2) (x - 1))/(x(x+1))) = #

#= ln(lim_(x->oo)(e (1 + 2/x) (1 - 1/x))/((1+1/x))) = ln(e xx 1)=1#